Pour vous laisser savoir mieux que la Q&A Oracle 1z1-061 produit par Pass4Test est persuadante, le démo de Q&A Oracle 1z1-061 est gratuit à télécharger. Sous l'aide de Pass4Test, vous pouvez non seulement passer le test à la première fois, mais aussi économiser vos temps et efforts. Vous allez trouver les questions presque même que lesquels dans le test réel. C'est pourquoi tous les candidats peuvent réussir le test Oracle 1z1-061 sans aucune doute. C'est aussi un symbole d'un meilleur demain de votre carrière.
Pass4Test est un site professionnel qui répondre les demandes de beaucoup clients. Les candidats qui ont déjà passer leurs premiers test Certification IT ont devenus les suivis de Pass4Test. Grâce à la bonne qualité des documentations, Pass4Test peut aider tous candidats à réussir le test Oracle 1z1-061.
Pass4Test, où vous pouvez trouver les conseils et les documentations de test Certification Oracle 1z1-061, est un siteweb remarquable offrant les données à préparer le test IT. Les documentations partiels et les mis en nouveau sont offerts gratuitement dans le site de Pass4Test. D'ailleurs, nos experts profitent de leurs expériences et leurs efforts à lancer sans arrêts les Q&A plus proches au test réel. Vous allez passer votre examen plus facile.
Code d'Examen: 1z1-061
Nom d'Examen: Oracle (Oracle Database 12c: SQL Fundamentals)
Questions et réponses: 75 Q&As
Les experts de Pass4Test profitent de leurs expériences et connaissances à augmenter successivement la qualité des docmentations pour répondre une grande demande des candidats, juste pour que les candidats soient permis à réussir le test Oracle 1z1-061 par une seule fois. Vous allez avoir les infos plus proches de test réel à travers d'acheter le produti de Pass4Test. Notre confiance sont venue de la grande couverture et la haute précision de nos Q&As. 100% précision des réponses vous donnent une confiance 100%. Vous n'auriez pas aucun soucis avant de participer le test.
1z1-061 Démo gratuit à télécharger: http://www.pass4test.fr/1z1-061.html
NO.1 Examine the structure proposed for the transactions table:
Which two statements are true regarding the creation and storage of data in the above table
structure?
A. The CUST_STATUS column would give an error.
B. The TRANS_VALIDITY column would give an error.
C. The CUST_STATUS column would store exactly one character.
D. The CUST_CREDIT_LIMIT column would not be able to store decimal values.
E. The TRANS_VALIDITY column would have a maximum size of one character.
F. The TRANS_DATE column would be able to store day, month, century, year, hour, minutes,
seconds, and fractions of seconds
Answer: B,C
Oracle examen 1z1-061 1z1-061 1z1-061 1z1-061 examen 1z1-061 examen
Explanation:
VARCHAR2(size)Variable-length character data (A maximum size must be specified:
minimum size is 1; maximum size is 4, 000.)
CHAR [(size)] Fixed-length character data of length size bytes (Default and minimum size
is 1; maximum size is 2, 000.)
NUMBER [(p, s)] Number having precision p and scale s (Precision is the total number of
decimal digits and scale is the number of digits to the right of the decimal point; precision
can range from 1 to 38, and scale can range from -84 to 127.)
DATE Date and time values to the nearest second between January 1, 4712 B.C., and
December 31, 9999 A.D.
NO.2 In the customers table, the CUST_CITY column contains the value 'Paris' for the
CUST_FIRST_NAME 'Abigail'.
Evaluate the following query:
What would be the outcome?
A. Abigail PA
B. Abigail Pa
C. Abigail IS
D. An error message
Answer: B
Oracle 1z1-061 certification 1z1-061
NO.3 View the Exhibit and evaluate the structure and data in the CUST_STATUS table.
You issue the following SQL statement:
Which statement is true regarding the execution of the above query?
A. It produces an error because the AMT_SPENT column contains a null value.
B. It displays a bonus of 1000 for all customers whose AMT_SPENT is less than CREDIT_LIMIT.
C. It displays a bonus of 1000 for all customers whose AMT_SPENT equals CREDIT_LIMIT, or
AMT_SPENT is null.
D. It produces an error because the TO_NUMBER function must be used to convert the result of the
NULLIF function before it can be used by the NVL2 function.
Answer: C
Oracle examen certification 1z1-061 1z1-061 examen 1z1-061 examen certification 1z1-061
Explanation:
The NULLIF Function The NULLIF function tests two terms for equality. If they are equal the function
returns a null, else it returns the first of the two terms tested. The NULLIF function takes two
mandatory parameters of any data type. The syntax is NULLIF(ifunequal, comparison_term), where
the parameters ifunequal and comparison_term are compared. If they are identical, then NULL is
returned. If they differ, the ifunequal parameter is returned.
NO.4 You need to create a table for a banking application. One of the columns in the table has the
following requirements:
1. You want a column in the table to store the duration of the credit period.
2) The data in the column should be stored in a format such that it can be easily added and
subtracted with date data type without using conversion functions.
3) The maximum period of the credit provision in the application is 30 days.
4) The interest has to be calculated for the number of days an individual has taken a credit for.
Which data type would you use for such a column in the table?
A. DATE
B. NUMBER
C. TIMESTAMP
D. INTERVAL DAY TO SECOND
E. INTERVAL YEAR TO MONTH
Answer: D
Oracle 1z1-061 examen 1z1-061 examen
NO.5 View the Exhibit and examine the structure of the product, component, and PDT_COMP
tables.
In product table, PDTNO is the primary key.
In component table, COMPNO is the primary key.
In PDT_COMP table, <PDTNO, COMPNO) is the primary key, PDTNO is the foreign key referencing
PDTNO in product table and COMPNO is the foreign key referencing the COMPNO in component
table.
You want to generate a report listing the product names and their corresponding component names,
if the component names and product names exist.
Evaluate the following query:
SQL>SELECT pdtno, pdtname, compno, compname
FROM product _____________ pdt_comp
USING (pdtno) ____________ component USING (compno)
WHERE compname IS NOT NULL;
Which combination of joins used in the blanks in the above query gives the correct output?
A. JOIN; JOIN
B. FULL OUTER JOIN; FULL OUTER JOIN
C. RIGHT OUTER JOIN; LEFT OUTER JOIN
D. LEFT OUTER JOIN; RIGHT OUTER JOIN
Answer: C
Oracle 1z1-061 1z1-061
NO.6 Which normal form is a table in if it has no multi-valued attributes and no partial
dependencies?
A. First normal form
B. Second normal form
C. Third normal form
D. Fourth normal form
Answer: B
Oracle examen 1z1-061 1z1-061
NO.7 View the Exhibit for the structure of the student and faculty tables.
You need to display the faculty name followed by the number of students handled by the faculty at
the base location.
Examine the following two SQL statements:
Which statement is true regarding the outcome?
A. Only statement 1 executes successfully and gives the required result.
B. Only statement 2 executes successfully and gives the required result.
C. Both statements 1 and 2 execute successfully and give different results.
D. Both statements 1 and 2 execute successfully and give the same required result.
Answer: D
Oracle 1z1-061 examen 1z1-061 certification 1z1-061
NO.8 Evaluate the following SQL statement:
Which statement is true regarding the outcome of the above query?
A. It executes successfully and displays rows in the descending order of PROMO_CATEGORY .
B. It produces an error because positional notation cannot be used in the order by clause with set
operators.
C. It executes successfully but ignores the order by clause because it is not located at the end of the
compound statement.
D. It produces an error because the order by clause should appear only at the end of a compound
query-that is, with the last select statement.
Answer: D
Oracle examen 1z1-061 1z1-061
NO.9 Which three tasks can be performed using SQL functions built into Oracle Database?
A. Displaying a date in a nondefault format
B. Finding the number of characters in an expression
C. Substituting a character string in a text expression with a specified string
D. Combining more than two columns or expressions into a single column in the output
Answer: A,B,C
Oracle examen 1z1-061 1z1-061 examen certification 1z1-061
NO.10 Examine the types and examples of relationships that follow:
1.One-to-one a) Teacher to students
2.One-to-many b) Employees to Manager
3.Many-to-one c) Person to SSN
4.Many-to-many d) Customers to products
Which option indicates the correctly matched relationships?
A. 1-a, 2-b, 3-c, and 4-d
B. 1-c, 2-d, 3-a, and 4-b
C. 1-c, 2-a, 3-b, and 4-d
D. 1-d, 2-b, 3-a, and 4-c
Answer: C
Oracle 1z1-061 certification 1z1-061
Est-ce que vous vous souciez encore pour passer le test Oracle 1z1-061? Pourquoi pas choisir la formation en Internet dans une société de l'informatique. Un bon choix de l'outil formation peut résoudre le problème de prendre grande quantité de connaissances demandées par le test Oracle 1z1-061, et vous permet de préparer mieux avant le test. Les experts de Pass4Test travaillent avec tous efforts à produire une bonne Q&A ciblée au test Oracle 1z1-061. La Q&A est un bon choix pour vous. Vous pouvez télécharger le démo grantuit tout d'abord en Internet.
没有评论:
发表评论